ENGLEWOOD, Colo. — After a stellar performance in his return to Houston, Kareem Jackson has been named the AFC Defensive Player of the Week, the NFL announced Wednesday.
Jackson earned the honor after he recorded 11 tackles, three passes defensed, an interception and a 70-yard fumble return for a touchdown against the Texans in Week 14.
He is just the third player in NFL history to record 10 or more tackles, an interception and a fumble return for a touchdown in the same game, according to Pro Football Reference.
This is the first time in Jackson's career that he has won the award.
Jackson is the first Broncos player to earn AFC Player of the Week honors in 2019, and he is the first Broncos defender since Von Miller to earn the award.
Miller earned the award after his Week 11 performance against the Chargers last season.
Running back Phillip Lindsay is the most recent Broncos player to win AFC honors, as he won the offensive award after the Broncos' Week 13 game last year.